Parse string into map Golang

2021-6-21 anglehua

I have a string like A=B&C=D&E=F, how to parse it into map in golang?

Here is example on Java, but I don't understand this split part

String text = "A=B&C=D&E=F";
Map<String, String> map = new LinkedHashMap<String, String>();
for(String keyValue : text.split(" *& *")) {
   String[] pairs = keyValue.split(" *= *", 2);
   map.put(pairs[0], pairs.length == 1 ? "" : pairs[1]);

Maybe what you really want is to parse an HTTP query string, and url.ParseQuery does that. (What it returns is, more precisely, a url.Values storing a []string for every key, since URLs sometimes have more than one value per key.) It does things like parse HTML escapes (%0A, etc.) that just splitting doesn't. You can find its implementation if you search in the source of url.go.

However, if you do really want to just split on & and = like that Java code did, there are Go analogues for all of the concepts and tools there:

  • map[string]string is Go's analog of Map<String, String>
  • strings.Split can split on & for you. SplitN limits the number of pieces split into like the two-argument version of split() in Java does. Note that there might only be one piece so you should check len(pieces) before trying to access pieces[1] say.
  • for _, piece := range pieces will iterate the pieces you split.
  • The Java code seems to rely on regexes to trim spaces. Go's Split doesn't use them, but strings.TrimSpace does something like what you want (specifically, strips all sorts of Unicode whitespace from both sides).

I'm leaving the actual implementation to you, but perhaps these pointers can get you started.

import ( "strings" )

var m map[string]string
var ss []string

s := "A=B&C=D&E=F"
ss = strings.Split(s, "&")
m = make(map[string]string)
for _, pair := range ss {
    z := strings.Split(pair, "=")
    m[z[0]] = z[1]

This will do what you want.


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