How to parse JSON in Java
2021-6-3 anglehua
I have the following JSON text. How can I parse it to get the values of pageName
, pagePic
, post_id
, etc.?
{
"pageInfo": {
"pageName": "abc",
"pagePic": "http://example.com/content.jpg"
},
"posts": [
{
"post_id": "123456789012_123456789012",
"actor_id": "1234567890",
"picOfPersonWhoPosted": "http://example.com/photo.jpg",
"nameOfPersonWhoPosted": "Jane Doe",
"message": "Sounds cool. Can't wait to see it!",
"likesCount": "2",
"comments": [],
"timeOfPost": "1234567890"
}
]
}
The org.json library is easy to use.
Just remember (while casting or using methods like getJSONObject
and getJSONArray
) that in JSON notation
[ … ]
represents an array, so library will parse it to JSONArray
{ … }
represents an object, so library will parse it to JSONObject
Example code below:
import org.json.*;
String jsonString = ... ; //assign your JSON String here
JSONObject obj = new JSONObject(jsonString);
String pageName = obj.getJSONObject("pageInfo").getString("pageName");
JSONArray arr = obj.getJSONArray("posts"); // notice that `"posts": [...]`
for (int i = 0; i < arr.length(); i++)
{
String post_id = arr.getJSONObject(i).getString("post_id");
......
}
You may find more examples from: Parse JSON in Java
Downloadable jar: http://mvnrepository.com/artifact/org.json/json
For the sake of the example lets assume you have a class Person
with just a name
.
private class Person {
public String name;
public Person(String name) {
this.name = name;
}
}
My personal favourite as to the great JSON serialisation / de-serialisation of objects.
Gson g = new Gson();
Person person = g.fromJson("{\"name\": \"John\"}", Person.class);
System.out.println(person.name); //John
System.out.println(g.toJson(person)); // {"name":"John"}
Update
If you want to get a single attribute out you can do it easily with the Google library as well:
JsonObject jsonObject = new JsonParser().parse("{\"name\": \"John\"}").getAsJsonObject();
System.out.println(jsonObject.get("name").getAsString()); //John
If you don't need object de-serialisation but to simply get an attribute, you can try org.json (or look GSON example above!)
JSONObject obj = new JSONObject("{\"name\": \"John\"}");
System.out.println(obj.getString("name")); //John
ObjectMapper mapper = new ObjectMapper();
Person user = mapper.readValue("{\"name\": \"John\"}", Person.class);
System.out.println(user.name); //John
采集自互联网,如有侵权请联系本人